What is the electronic potential at the centre of square of side 1 m? The charges 1×10−8C,−2×10−8C,3×10−8Cand2×10−8C are placed at the corners of the square.
qA=10−8C
qB=−2×10−8C
qB=3×10−8C
qD=2×10−8C
a=1m
r=√22=1√2m
VA=14πε0.qAr =9×109×10−8×√2=90√2J
VB=14πε0.qBr =9×109×10−8×−2√2=−180√2J
VC=14πε0.qCr =9×109×10−8×3√2=270√2J
VD=14πε0.qDr =9×109×10−8×2√2=180√2J
Vnet=VA+VB+VC+VD=360√2J