What is the hybridization state of cation part of solid $P C l_{5}$ ?

Question

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Answer 1

In solid state, $P C l_{5}$ prefers to exist as oppositely charged ions like $[P C l_{4}]^{+} P C l_{6}^{-}$ as ionic bonding enhances the crystalline nature. Also, $[P C l_{4}]^{+} = s p^{3}$ is tetrahedral while $[P C l_{6}^{-}]$ is octahedral. These structures fit well into each other providing extra stability to the soild structure.
Thus, solid $P C l_{5}$ exist as $[P C l_{4}]^{+} [P C l_{6}]^{-}$
The cationic part of $P C l_{5}$ is $[P C l_{4}]^{+}$ .
In $P C l_{4}^{+}$ , Phosphorous forms $4 σ - b o n d s$ .
Hence, the hybridization is $s p^{3}$ .

Answer 2

In solid state,

P C l_{5}

prefers to exist as oppositely charged ions like

[P C l_{4}]^{+} P C l_{6}^{-}

as ionic bonding enhances the crystalline nature. Also,

[P C l_{4}]^{+} = s p^{3}

is tetrahedral while

[P C l_{6}^{-}]

is octahedral. These structures fit well into each other providing extra stability to the soild structure.

Thus, solid

P C l_{5}

exist as

[P C l_{4}]^{+} [P C l_{6}]^{-}

The cationic part of

P C l_{5}

is

[P C l_{4}]^{+}

.
In

P C l_{4}^{+}

, Phosphorous forms

4 σ - b o n d s

.

Hence, the hybridization is

s p^{3}

.

What is the hybridization state of cation part of solid $P C l_{5}$ ?

$s p^{3} d^{2}$

$s p^{2}$

$s p^{3}$

$s p^{3} d$

The hybridization state of the central atom in $P C l_{5}$ is:

The solid $P C l_{5}$ exists as :

In solid state $P C l_{5}$ exist as an ionic solid $[P C l_{4}]^{+} [P C l_{6}]^{-}$ hybridisation state of cation and anion respectively :

$N_{2} O_{5}$ is said to be ionic in solid state. Write the cation and anion in it and the hybridised state of N atom in cation.

In which of the following molecule, the number of possible $∠ X A X$ angles is maximum in the anionic part of their solid state? [ $A :$ Central atom, $X :$ surrounding atom]

Revise with Concepts

Compounds of Phosphorus - PCl3

Compounds of Phosphorus - PCl5

What is the hybridization state of cation part of solid PCl5​?

sp3d2

sp2

sp3

sp3d

The hybridization state of the central atom in PCl5​ is:

The solid PCl5​ exists as :

In solid state PCl5​ exist as an ionic solid [PCl4​]+[PCl6​]− hybridisation state of cation and anion respectively :

N2​O5​ is said to be ionic in solid state. Write the cation and anion in it and the hybridised state of N atom in cation.

In which of the following molecule, the number of possible ∠XAX angles is maximum in the anionic part of their solid state? [A: Central atom, X: surrounding atom]

Revise with Concepts

Compounds of Phosphorus - PCl3

Compounds of Phosphorus - PCl5

What is the hybridization state of cation part of solid $P C l_{5}$ ?

$s p^{3} d^{2}$

$s p^{2}$

$s p^{3}$

$s p^{3} d$

The hybridization state of the central atom in $P C l_{5}$ is:

The solid $P C l_{5}$ exists as :

In solid state $P C l_{5}$ exist as an ionic solid $[P C l_{4}]^{+} [P C l_{6}]^{-}$ hybridisation state of cation and anion respectively :

$N_{2} O_{5}$ is said to be ionic in solid state. Write the cation and anion in it and the hybridised state of N atom in cation.

In which of the following molecule, the number of possible $∠ X A X$ angles is maximum in the anionic part of their solid state? [ $A :$ Central atom, $X :$ surrounding atom]