What is the length of the outer boundary of the park shown in Figure. What will be the total cost of fencing it at the rate of Rs.20 per meter? There is a rectangular flower bed in the centre of the park. Find the cost of manuring the flower bed at the rate of Rs.50 per square meter.
Addition of all Sides of Given figure is called perimeter
∴ Perimeter of the given figure =(200+300+80+300+200+260)m=1340 m
∴ Total cost of fencing it at the rate of Rs.20 per meter
=Rs.(1340×20)=Rs.26800
∴ Area of the flower bed =(100×80)m2=8000 m2
Now, cost of manuring the flower bed at the rate of Rs.50 per square meter =Rs.(50×8000)=Rs.400000.
Question 39
What is the length of outer boundary of the park shown in the given figure? What will be the total cost of fencing it at the rate of Rs 20 per metre? There is a rectangular flower bed in the center of the park. Find the cost of manuring the flower bed at the rate of Rs 50 per square metre.
Question 82
In a rectangular plot, 5 square flower beds of side (x+2) metres each have been laid (see the figure). Find the total cost of fencing the flower beds at the cost of Rs. 50 per 100 meters.
In a rectangular plot, 5 square flower beds of side (x+2) metres each have been laid (see the figure). Find the total cost of fencing the flower beds at the cost of ₹50 per 100 meters.
In a park of dimensions 20m×15m, there is an L shaped 1m wide flower bed as shown in the figure. Find the total cost of manuring for the flower bed at the rate of ₹ 45 per m2.
