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Question

# What is the magnification of an astronomical telescope whose objective lens has a focal length of 82 cm, and whose eyepiece has a focal length of 2.8 cm?

A
$$15X$$
B
$$22X$$
C
$$29X$$
D
$$33X$$
Solution
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#### Correct option is C. $$29X$$The negative ratio of focal length of the objective to the focal length of the eyepiece give the focal length of the telescope$$M=-\dfrac{f_0}{f_{e}}$$Here, $$f_0$$ is focal length, M is magnification and $$f_e$$ is eyepiece of focal lengthSubstitute $$2.8$$ cm for $$f_{e}$$, and $$82cm$$ for $$f_0$$$$M=-\dfrac{82}{2.8}=-29X$$

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