What is the magnitude of the gravitational force between the earth and a $1 k g$ object on its surface? (Mass of the earth is $6 \times 10^{24} k g$ and radius of the earth is $6.4 \times 10^{6} m$ .)

Question

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface- -Mass of the earth is 6times 10-24- kg and radius of the earth is 6-4times 10-6 m-

Toppr Admin · Accepted Answer

Given - -xA0- -xA0- -xA0- Mass of earth -xA0- -xA0-M-6-xD7-1024-xA0-kg-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-Mass of object -xA0- -xA0-m-1-xA0-kg-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- Radius of earth -xA0- -xA0- -xA0- R-6-4-xD7-106-xA0-m-xA0-Force of gravitation between them- F-GMmR2F-6-67-xD7-10-x2212-11-xD7-6-xD7-1024-xD7-1-6-4-xD7-106-2-9-77-xA0-N-xA0-

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6×1024 kg and radius of the earth is 6.4×106 m.)

Given : Mass of earth M=6×1024 kg Mass of object m=1 kg Radius of earth R=6.4×106 m Force of gravitation between them, F=GMmR2F=6.67×10−11×(6×1024)×1(6.4×106)2=9.77 N

What is the magnitude of the gravitational force between the earth and a $1 k g$ object on its surface? (Mass of the earth is $6 \times 10^{24} k g$ and radius of the earth is $6.4 \times 10^{6} m$ .)

Given : Mass of earth $M = 6 \times 10^{24} k g$
Mass of object $m = 1 k g$
Radius of earth $R = 6.4 \times 10^{6} m$
Force of gravitation between them, $F = \frac{G M m}{R^{2}}$
$F = \frac{6.67 \times 10^{- 11} \times (6 \times 10^{24}) \times 1}{(6.4 \times 10^{6})^{2}} = 9.77 N$