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Standard VI
Physics
Static Friction
Question
What is the maximum value of the force F such that the block shown in figure does not move
10
N
20
N
12
N
15
N
A
20
N
B
10
N
C
12
N
D
15
N
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Solution
Verified by Toppr
For vertical equilibrium of the block
N
=
m
g
+
F
s
i
n
60
0
=
√
3
g
+
√
3
F
2
For no motion, force of friction
f
≥
F
cos
60
0
o
r
μ
N
≥
F
cos
60
0
1
2
√
3
(
√
3
g
+
√
3
F
2
)
≥
F
2
⇒
g
≥
F
2
⇒
F
≤
2
g
o
r
20
N
Therefore , maximum value of
F
is
20
N
.
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