What is the measured component of the orbital magnetic the dipole moment of an electron with the values (a)$$m_l=3$$ and
(b)$$m_l=-4$$ ?

Question

What is the measured component of the orbital magnetic dipole moment of an electron with -a-m-l-1 and -b-m-l-2-

Toppr Admin · Accepted Answer

As we know-We use - -956-orb- z- - -8211- m-l -956-B-a- For -m-l - 1- -956-orb-z- - -8211-1- -9-3 -times 10-8211-24- J-T- - -8211-9-3 -times 10-8211-24- J-T-160-b- For -m-l - -2- -956-orb-z- - -8211-2- -9-3 -times 10-8211-24- J-T- - 1-9 -times 10-8211-23- J-T-160-

What is the measured component of the orbital magnetic dipole moment of an electron with (a)$$m_l=1$$ and (b)$$m_l=-2$$?

As we know,
We use : $$μ_{orb, z} = – m_l μ_B$$.
(a) For $$m_l = 1$$, $$μ_{orb,z} = –(1) (9.3 \times 10^{–24}\, J/T) = –9.3 \times 10^{–24}\, J/T$$.
(b) For $$m_l = -2$$, $$μ_{orb,z} = –(-2) (9.3 \times 10^{–24}\, J/T) = 1.9 \times 10^{–23}\, J/T$$.

What is the measured component of the orbital magnetic dipole moment of an electron with (a)$$m_l=1$$ and (b)$$m_l=-2$$?

As we know,We use : $$μ_{orb, z} = – m_l μ_B$$.(a) For $$m_l = 1$$, $$μ_{orb,z} = –(1) (9.3 \times 10^{–24}\, J/T) = –9.3 \times 10^{–24}\, J/T$$. (b) For $$m_l = -2$$, $$μ_{orb,z} = –(-2) (9.3 \times 10^{–24}\, J/T) = 1.9 \times 10^{–23}\, J/T$$.

As we know,
We use : $$μ_{orb, z} = – m_l μ_B$$.
(a) For $$m_l = 1$$, $$μ_{orb,z} = –(1) (9.3 \times 10^{–24}\, J/T) = –9.3 \times 10^{–24}\, J/T$$.
(b) For $$m_l = -2$$, $$μ_{orb,z} = –(-2) (9.3 \times 10^{–24}\, J/T) = 1.9 \times 10^{–23}\, J/T$$.