What is the molarity of a solution containing $10 g$ of $N a O H$ in $500 m L$ of the solution?
$0.75 m o l$ $L^{- 1}$
$0.25 m o l$ $L^{- 1}$
$0.5 m o l$ $L^{- 1}$
$1.25 m o l$ $L^{- 1}$

Question

What is the molarity of a solution containing 10g of NaOH in 500 mL of the solution-0-75 mol -L-1-0-25 mol -L-1-0-5 mol -L-1-1-25 mol -L-1-

Toppr Admin · Accepted Answer

Molarity - n-xD7-1000VmlMolar mass of NaOH - 40g-molNo of moles of NaOH - 1040-0-25moltherefore Molarity - 0-25-xD7-1000500-250500-0-5molL-x2212-1Hence- the correct option is C

What is the molarity of a solution containing 10g of NaOH in 500 mL of the solution?0.75 mol L−10.25 mol L−10.5 mol L−11.25 mol L−1

Molarity = n×1000VmlMolar mass of NaOH = 40g/molNo of moles of NaOH = 1040=0.25moltherefore Molarity = 0.25×1000500=250500=0.5molL−1Hence, the correct option is C

What is the molarity of a solution containing $10 g$ of $N a O H$ in $500 m L$ of the solution?
$0.75 m o l$ $L^{- 1}$
$0.25 m o l$ $L^{- 1}$
$0.5 m o l$ $L^{- 1}$
$1.25 m o l$ $L^{- 1}$

Molarity = $\frac{n \times 1000}{V_{m l}}$

Molar mass of $N a O H$ = $40 g / m o l$

No of moles of $N a O H$ = $\frac{10}{40} = 0.25 m o l$

therefore Molarity = $\frac{0.25 \times 1000}{500} = \frac{250}{500} = 0.5 m o l L^{- 1}$

Hence, the correct option is $C$