What is the moment of inertia of ring about its diameter ?
$M R^{2}$
$\frac{M R^{2}}{2}$
$\frac{3 M R^{2}}{4}$
$\frac{5 M R^{2}}{4}$

\frac{5 M R^{2}}{4}

\frac{M R^{2}}{2}

\frac{3 M R^{2}}{4}

M R^{2}

Open in App

Solution

Verified by Toppr

Was this answer helpful?

Similar Questions

All sheets are of same mass $\frac{M}{2}$ each but radius $R, \frac{R}{2}, \frac{R}{4}, \frac{R}{8}$ .......There are infinitesheets. What is the moment of inertia about the center?

View Solution

2/459.Moment of inertia of a solid hemi-sphere ofmass m, radius R about the axis which isparallel to its diameter (as shown in figure).CM3R/8(1)mR2(2)mR21(3)mR2(4)mR2

View Solution

Find the moment of inertia of ring of mass

M

and radius

R

about the axis passing through the ring diametrically. If moment of inertia about the axis passing through its center of mass and perpendicular to the plane is

M R^{2}

View Solution

State parallel axis theorem.what is the moment of inertia of disc about its diameter?(moment of inertia of disc about an axis perpendicular to plane at its centre is MR²/2)

View Solution

The moment of inertia of a solid disc made of thin metal of radius

R

and mass

M

about one of its diameters is given by

\frac{{M R}^{2}}{4}

. What will be moment of inertia about this axis if the disc if folded in half about this diameter?

View Solution

What is the moment of inertia of ring about its diameter ?MR2MR223MR245MR24

What is the moment of inertia of ring about its diameter ?
$M R^{2}$
$\frac{M R^{2}}{2}$
$\frac{3 M R^{2}}{4}$
$\frac{5 M R^{2}}{4}$