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Standard XII
Chemistry
Question
What is the normality of 96% w/w aqueous
H
2
S
O
4
solution?
(Atomic weight of
H
=
1
,
S
=
32
,
O
=
16
, density
=
1.84
gm/L)
Open in App
Solution
Verified by Toppr
Percentage of
W
/
W
=
96
⇒
96
=
Weight of
H
2
S
O
4
(
W
)
×
100
Weight of
H
2
S
O
4
+
Weight of water (WL)
⇒
96
100
=
W
W
+
W
2
Solving,
W
=
24
W
L
Weight of
H
2
S
O
4
=
24
Weight of
H
2
O
Normality=
Weight of
H
2
S
O
4
GEW of
H
2
S
O
4
×
1000
Volume of
H
2
S
O
4
=
24
W
L
49
×
1000
Volume of
H
2
O
Density=
1.84
g
/
L
⇒
W
L
Volume of
H
2
O
=
1.84
⇒
Volume of
H
2
O
=
W
L
1.84
⇒
24
W
L
49
×
1000
W
L
1.84
⇒
24
×
1.84
×
1000
49
=
901.22
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Similar Questions
Q1
What is the normality of 96% w/w aqueous
H
2
S
O
4
solution?
(Atomic weight of
H
=
1
,
S
=
32
,
O
=
16
, density
=
1.84
gm/L)
View Solution
Q2
Battery acid ia
4.22
M
aqueous
H
2
S
O
4
solution, and has density fo
1.21
g
c
m
−
3
. What is the molality of
H
2
S
O
4
? H=1, S=32, O=16
(
m
=
5.298
m
o
l
k
g
−
1
)
View Solution
Q3
Find the molality of the solution having
93
%
H
2
S
O
4
(
w
/
v
) having density
1.84
g
m
L
−
1
is:
View Solution
Q4
The volume required to prepare
2.0
L
of
3.0
M
H
2
S
O
4
solution from
96
%
( w/w)
H
2
S
O
4
solution (density
=
2
g
mL
−
1
) is
View Solution
Q5
Calculate the molality of a
1
L
soluttion of
93
%
H
2
S
O
4
(w/V) . The density of the solution is
1.84
g
m
L
−
1
View Solution