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What is the pOH of a 0.5 M Na3PO4 solution ? Report your answer as 10 POH. (K. = 7.5 x 10-3, Ka, = 6.2 x 10-8, K, = 4 x 10-13) What is the poth, 0.5 m Na solution Paperport your answer a:

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Similar Questions

Q1

Considering a

0.1 M H_{3} P O_{4}

solution, answer the questions given below:
[Given :

K_{1} = 7.5 \times 10^{- 3}, K_{2} = 6.2 \times 10^{- 8}, K_{3} = 3.6 \times 10^{- 13}

]
In the given solution

[H^{+}]

&

[H_{2} P O_{4}^{-}]

is:

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Q2

Calcium lactate

C a (L a c)_{2}

is salt of weak organic acid. A saturated solution of

C a (L a c)_{2}

contains 0.13 mole of this salt in 0.5 litre solution. The pOH of this solution is 5.60. Assuming a complete dissociation of salt, calculate

K_{a}

lactic acid

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Q3

Considering 0.1 M

H_{3} {P O}_{4}

(Given:

K_{1} = {7.5 \times 10}^{- 3}

K_{2} = {6.2 \times 10}^{- 8}

K_{3} = {3.6 \times 10}^{- 13}

)

In the given solution

[H^{+}] & [H_{2} {P O}_{4}^{-}]

is

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Q4

What is

p O H

of an aqueous solution with

[H^{+}]

=

10^{- 2} M

K_{w} = 2 \times 10^{- 12}

? Report your answer after dividing by 2 and round it off to the nearest whole number.
Percentage ionisation of water as follows at certain temperature is

3.6

\times

10^{- 7}

%. Calculate

K_{w}

and

p H

of water temperature.

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Q5

What is the

p O H

of a buffer solution containing

0.04

moles of acetic acid and

0.4

moles of potassium acetate?

(K_{a} = 10^{- 5})

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