What is the probability that in a group of -N- people- least two of them have the same birthday-

Question

Toppr Admin · Accepted Answer

Assuming the peoples in the group are born in a non leap year-xA0-probability of two persons have the same birthdate -1365-xD7-1365-xA0-probability that atleast two of the people having same birthday -Nc2365-xD7-365

What is the probability that in a group of $^{'} N^{'}$ people, at least two of them have the same birthday.

assuming the peoples in the group are born in a non leap year.
probability of two persons have the same birthdate $= \frac{1}{365} \times \frac{1}{365}$
probability that atleast two of the people having same birthday $= \frac{N c_{2}}{365 \times 365}$

What is the probability that in a group of ′N′ people, at least two of them have the same birthday.

assuming the peoples in the group are born in a non leap year. probability of two persons have the same birthdate =1365×1365 probability that atleast two of the people having same birthday =Nc2365×365

What is the probability that in a group of $^{'} N^{'}$ people, at least two of them have the same birthday.

assuming the peoples in the group are born in a non leap year.
probability of two persons have the same birthdate $= \frac{1}{365} \times \frac{1}{365}$
probability that atleast two of the people having same birthday $= \frac{N c_{2}}{365 \times 365}$