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What is the relationship between Gibbs free energy of the cell reaction in a galvanic cell and the emf of the cell? When will the maximum work be obtained from a galvanic cell?

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Similar Questions
Q1
What is the relationship between Gibbs free energy of the cell reaction in a galvanic cell and the EMF of the cell? When will the maximum work be obtained from a galvanic cell?
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Q2
Assertion :To obtain maximum work from a galvanic cell charge has to be passed reversibly. Reason: The reversible work done by a galvanic cell is equal to decrease in its Gibbs energy.
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Q3
Reason
The reversible work done by a galvanic cell is equal to decrease in its Gibbs energy.
Assertion
To obtain maximum work from a galvanic cell charge has to be passed reversibly.
To obtain maximum work from a galvanic cell charge has to be passed reversibly.
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Q4
Electrical work done in one second is equal to electrical potential multiplied by total charge passed. If we want to obtain maximum work from a galvanic cell then charge has to be passed reversibly. The reversible work done by a galvanic cell is equal to decrease in its Gibbs energy and therefore, if the emf of the cell is E and nF is the amount of charge passed and ΔrG is the Gibbs energy of the reaction, then
ΔrG=nFE(cell)
It may be remembered that E(cell) is an intensive parameter but ΔrG is an extensive thermodynamic property and the value depends on n. Thus, if we write the reaction.
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Q5

How can we say that the reversible work done by the galvanic cell is equal to decrease in its Gibbs energy?

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