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Question

What is the time (in/sec) taken by a 180 m long train running at 54 km/h to cross a man standing on a platform?

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Solution

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Distance = 180 m
speed = 54km/n=54000 m/n
Distance= $s p e e d \times t i m e$
$t i m e = \frac{d i s t a n c e}{s p e e d}$
$\frac{180}{54000}$ hr
$\frac{180 \times 60}{54000} m i n = 0.2 m i n$
= 12.5 sec

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