What is the value of Delta n-g we consider the combustion of 1 mol of liquid ethanol reactants and produces are 298 K-1-212

Question

Toppr Admin · Accepted Answer

The correct option is A -1-Ethanol- C2H5OH-l-3O2-x2192-2CO2-g-3H2O-l-x394-ng -Sum of gases at product side- -Sum of moles gases at reactant side-x394-ng -2-x2212-3-x2212-1

What is the value of $Δ n_{g}$ if we consider the combustion of 1 mol of liquid ethanol if reactants and produces are at 298 K:-
-1
-2
1
2

The correct option is A -1
(Ethanol) $C_{2} H_{5} O H (l) + 3 O_{2} \to 2 C O_{2} (g) + 3 H_{2} O (l)$
$Δ n_{g}$ =(Sum of gases at product side) -(Sum of moles gases at reactant side)
$Δ n_{g}$ $= 2 - 3 = - 1$

What is the value of Δng if we consider the combustion of 1 mol of liquid ethanol if reactants and produces are at 298 K:--1-212

The correct option is A -1(Ethanol) C2H5OH(l)+3O2→2CO2(g)+3H2O(l)Δng =(Sum of gases at product side) -(Sum of moles gases at reactant side)Δng =2−3=−1

What is the value of $Δ n_{g}$ if we consider the combustion of 1 mol of liquid ethanol if reactants and produces are at 298 K:-
-1
-2
1
2

The correct option is A -1
(Ethanol) $C_{2} H_{5} O H (l) + 3 O_{2} \to 2 C O_{2} (g) + 3 H_{2} O (l)$
$Δ n_{g}$ =(Sum of gases at product side) -(Sum of moles gases at reactant side)
$Δ n_{g}$ $= 2 - 3 = - 1$