What must be added to the of displaystyle 2a-2-3a-7-5a-2-2a-11 and displaystyle 3a-2-5a-8 to get 0-12-12displaystyle a-2-adisplaystyle a-1

Question

Toppr Admin · Accepted Answer

Let -apos-x-apos- be added to these polynomial to get 0-x21D2-2a2-x2212-3a-7-x2212-5a2-x2212-2a-x2212-11-3a2-5a-x2212-8-x-0-x21D2-2a2-x2212-5a2-3a2-x2212-3a-x2212-2a-5a-7-x2212-11-x2212-8-x-0-x21D2-0-0-x2212-12-x-0-x21D2-x-12Option B is correct-

What must be added to the sum of 2a2−3a+7,−5a2−2a−11 and 3a2+5a−8 to get 0?12−12a2+aa−1

Let 'x' be added to these polynomial to get 0.⇒(2a2−3a+7)+(−5a2−2a−11)+(3a2+5a−8)+x=0⇒(2a2−5a2+3a2)+(−3a−2a+5a)+(7−11−8)+x=0⇒0+0+(−12)+x=0⇒x=12Option B is correct.

What must be added to the sum of $2 a^{2} - 3 a + 7, - 5 a^{2} - 2 a - 11$ and $3 a^{2} + 5 a - 8$ to get $0$ ?
$12$
$- 12$
$a^{2} + a$
$a - 1$