Question

What number should be added to $$-1$$ so as to get $$\dfrac {5}{7}$$?

Answer 1

Let us consider $$x$$
$$-1 + x = \dfrac {5}{7}$$
Solving for $$x$$,
$$x = \dfrac {5}{7} - (-1) = \dfrac {5}{7} + 1$$
By taking LCM of $$2$$ and $$8$$ is $$8$$
$$\dfrac {5 + (1\times 7)}{7} = \dfrac {5 + 7}{7} = \dfrac {12}{7}$$
$$x = \dfrac {12}{7}$$
$$ \therefore \dfrac {12}{7}$$ should be added to $$-1$$ to get $$\dfrac {5}{7}$$.