What numbers should be added to dfrac-5-8- so as to get dfrac-3-2-dfrac-5-8-dfrac-7-8-dfrac-1-8-dfrac-7-8-

Question

Toppr Admin · Accepted Answer

Let-the required number is -x-Then-xA0-x-x2212-58-x2212-32-xA0-x-x2212-58-x2212-32 -xA0-x-x2212-32-58-x2212-12-58 -xA0-x-x2212-78 -Hence- this is the answer-

What numbers should be added to $\frac{- 5}{8}$ so as to get $\frac{- 3}{2}$ ?
$- \frac{5}{8}$
$\frac{7}{8}$
$- \frac{1}{8}$
$- \frac{7}{8}$

Let, the required number is $= x$

Then,

$x + (\frac{- 5}{8}) = \frac{- 3}{2}$

$x - \frac{5}{8} = \frac{- 3}{2}$

$x = - \frac{3}{2} + \frac{5}{8} = \frac{- 12 + 5}{8}$

$x = \frac{- 7}{8}$

Hence, this is the answer.

What numbers should be added to −58 so as to get −32?−5878−18−78

Let, the required number is =x Then, x+(−58)=−32 x−58=−32 x=−32+58=−12+58 x=−78 Hence, this is the answer.

What numbers should be added to $\frac{- 5}{8}$ so as to get $\frac{- 3}{2}$ ?
$- \frac{5}{8}$
$\frac{7}{8}$
$- \frac{1}{8}$
$- \frac{7}{8}$

Let, the required number is $= x$

Then,

$x + (\frac{- 5}{8}) = \frac{- 3}{2}$

$x - \frac{5}{8} = \frac{- 3}{2}$

$x = - \frac{3}{2} + \frac{5}{8} = \frac{- 12 + 5}{8}$

$x = \frac{- 7}{8}$

Hence, this is the answer.