What ratio of Pb-2- to Sn-2- conc- is needed to reverse following cell reaction-Sn-s-Pb-2-aq-rightleftharpoons Sn-2-aq-Pb-s-E-Sn-2-Sn-0-136V and E-Pb-2-Pb-0-126V0-4511-21-4

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Standard XII

Chemistry

Question

What ratio of $P b^{2 +}$ to $S n^{2 +}$ conc. is needed to reverse following cell reaction?
$S n (s) + P b^{2 +} (a q) ⇌ S n^{2 +} (a q) + P b (s);$
$E_{S n^{2 +} / S n} = - 0.136 V$ and $E_{P b^{2 +} / P b} = - 0.126 V$

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What ratio of Pb2+ to Sn2+ conc. is needed to reverse following cell reaction?Sn(s)+Pb2+(aq)⇌Sn2+(aq)+Pb(s);ESn2+/Sn=−0.136V and EPb2+/Pb=−0.126V0.4511.21.4

What ratio of $P b^{2 +}$ to $S n^{2 +}$ conc. is needed to reverse following cell reaction?
$S n (s) + P b^{2 +} (a q) ⇌ S n^{2 +} (a q) + P b (s);$
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0.45
1
1.2
1.4