What should be added to left- -dfrac- - 3-5- - dfrac- - 5-3- right- to get 1-

Question

Toppr Admin · Accepted Answer

We have-x2212-35-x2212-53-xA0-Let we add x in above expression- we have-x2212-35-x2212-53-x-1-x-1-35-53-x-15-9-2515-x-4915-xA0-Hence- the value of x is 4915-

What should be added to $[\frac{- 3}{5} + \frac{- 5}{3}]$ to get $1$ ?

We have,

$[\frac{- 3}{5} + \frac{- 5}{3}]$

Let we add $x$ in above expression, we have

$- \frac{3}{5} - \frac{5}{3} + x = 1$

$x = 1 + \frac{3}{5} + \frac{5}{3}$

$x = \frac{15 + 9 + 25}{15}$

$x = \frac{49}{15}$

Hence, the value of $x$ is $\frac{49}{15}$ .

What should be added to [−35+−53] to get 1?

We have, [−35+−53] Let we add x in above expression, we have −35−53+x=1 x=1+35+53 x=15+9+2515 x=4915 Hence, the value of x is 4915.

What should be added to $[\frac{- 3}{5} + \frac{- 5}{3}]$ to get $1$ ?

We have,

$[\frac{- 3}{5} + \frac{- 5}{3}]$

Let we add $x$ in above expression, we have

$- \frac{3}{5} - \frac{5}{3} + x = 1$

$x = 1 + \frac{3}{5} + \frac{5}{3}$

$x = \frac{15 + 9 + 25}{15}$

$x = \frac{49}{15}$

Hence, the value of $x$ is $\frac{49}{15}$ .