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What volume of propane is burnt for every 500 cm of air used in the reaction under the same conditions ? (Assuming oxygen is 1/5th of air) C3H8 + 5O2, -→ 3CO2, + 4H20

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Similar Questions
Q1

What volume of propane is burnt for every 500cm3 of air used in the reaction under the same conditions?
(Assuming oxygen is (15)th of air)


C3H8+5O23CO2+4H2O


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Q2
Propane burns in air according to the following equation:
C3H8+5O23CO2+4H2O.
What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?
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Q3

What volume of propane is burnt for every 100cm3 of oxygen used in the reaction?

C3H8+5O23CO2+4H2O

(gas volume measured under same conditions)


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Q4
What volume of oxygen gas (O2) measured at 0C and 1 atm is needed to burn 500 mL of propane gas (C3H8) completely, measured under the same conditions?
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Q5
Given: $$\mathrm{C_3H_8 + 5O_2 \rightarrow 3CO_2 +4H_2O}$$, How much propane is needed to react with $$6.2$$ moles of oxygen?
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