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Question

What will be the reduction potential for the following half-cell reaction at 298K?
(Given: [Ag+]=0.1M and Eocell=+0.80V)
  1. 0.741V
  2. 0.80V
  3. 0.80V
  4. 0.741V

A
0.80V
B
0.741V
C
0.80V
D
0.741V
Solution
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A galvanic cell or simple battery is made of two electrodes. Each of the electrodes of a galvanic cell is known as a half cell. In a battery, the two half cells form an oxidizing-reducing couple. When two half cells are connected via an electric conductor and salt bridge, an electrochemical reaction is started.

Nernst equation is,

Ecell=E0cell0.0591nlogQ

Here the reaction is,

Ag++eAg

n=1

E0cell=0.80V

Hence,

Ecell=E0cell0.0591nlog1[Ag+]

Ecell=0.800.05911log10.1

=0.741V

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