What will be the stable state of aggression of carbon at $298 K$ and 1 atm pressure?

Question

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Answer 1

Graphite has delocalized pi-electrons over the entire sheet. This delocalization lowers the energy of the system, leading to greater thermodynamic stability. Delocalization of electrons or greater conjugation - enhances the thermodynamic stability. Hence we see that graphite is the most stable among the given options.

Answer 2

Graphite has delocalized pi-electrons over the entire sheet. This delocalization lowers the energy of the system, leading to greater thermodynamic stability. Delocalization of electrons or greater conjugation - enhances the thermodynamic stability. Hence we see that graphite is the most stable among the given options.

What will be the stable state of aggression of carbon at $298 K$ and 1 atm pressure?

Graphite

Diamond

Amorphous carbon

None of these

Pressure is an intensive property.

The conventional standard molar enthalpy of an element in its stable state of aggrgation at $298 K$ is taken to be

The state of a mole of an ideal gas changed from state $A$ at pressure $2 P$ and volume $V$ follows four different processes and finally returns to initial state $A$ reversibly as shown in the graph, answer the following question.

Which is the kind of process followed from state $A$ to state $B$ ?

What will be the stable state of aggregation of sulphur at $298 K$ and 1 atm pressure?

Revise with Concepts

Introduction to Thermodynamics (Che)

State Functions and Path Functions

What will be the stable state of aggression of carbon at 298K and 1 atm pressure?

Graphite

Diamond

Amorphous carbon

None of these

Pressure is an intensive property.

The conventional standard molar enthalpy of an element in its stable state of aggrgation at 298K is taken to be

The state of a mole of an ideal gas changed from state A at pressure 2P and volume V follows four different processes and finally returns to initial state A reversibly as shown in the graph, answer the following question. Which is the kind of process followed from state A to state B?

What will be the stable state of aggregation of sulphur at 298 K and 1 atm pressure?

Revise with Concepts

Introduction to Thermodynamics (Che)

State Functions and Path Functions

What will be the stable state of aggression of carbon at $298 K$ and 1 atm pressure?

The conventional standard molar enthalpy of an element in its stable state of aggrgation at $298 K$ is taken to be

The state of a mole of an ideal gas changed from state $A$ at pressure $2 P$ and volume $V$ follows four different processes and finally returns to initial state $A$ reversibly as shown in the graph, answer the following question.

Which is the kind of process followed from state $A$ to state $B$ ?

What will be the stable state of aggregation of sulphur at $298 K$ and 1 atm pressure?