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Question

What will be the stable state of aggression of carbon at $298 K$ and 1 atm pressure?
Graphite
Amorphous carbon
Diamond
None of these

A

Graphite

B

Diamond

C

Amorphous carbon

D

None of these

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Solution

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Graphite has delocalized pi-electrons over the entire sheet. This delocalization lowers the energy of the system, leading to greater thermodynamic stability. Delocalization of electrons or greater conjugation - enhances the thermodynamic stability. Hence we see that graphite is the most stable among the given options.

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