Solve
Guides
Join / Login
Use app
Login
0
You visited us
0
times! Enjoying our articles?
Unlock Full Access!
Standard XII
Chemistry
Question
What would happen when as solution of potassium chromate is treated with an excess of dilute nitric acid?
C
r
3
+
and
C
r
2
O
2
−
7
are formed
C
r
2
O
2
−
7
ang
H
2
O
are formed
None of the above
C
r
O
2
−
4
is reduced to
C
r
3
+
A
C
r
2
O
2
−
7
ang
H
2
O
are formed
B
C
r
3
+
and
C
r
2
O
2
−
7
are formed
C
None of the above
D
C
r
O
2
−
4
is reduced to
C
r
3
+
Open in App
Solution
Verified by Toppr
Reaction:
C
r
O
2
−
4
+
2
H
+
→
C
r
2
O
2
−
7
+
H
2
O
Was this answer helpful?
0
Similar Questions
Q1
What would happen when as solution of potassium chromate is treated with an excess of dilute nitric acid?
View Solution
Q2
What would happen when solution of potassium chromate is treated with the excess of nitric acid?
View Solution
Q3
What happens when a solution of pottasium chromate is treated with an excess of dilute nitric acid?
View Solution
Q4
The complete balanced equation in acid medium is:
H
2
S
O
3
+
C
r
2
O
2
−
7
→
H
2
S
O
4
+
C
r
3
+
+
H
2
O
View Solution
Q5
In a reaction ,
C
r
2
O
2
−
7
is reduced to
C
r
3
+
. What is concentration of 0.1 M
K
2
C
r
2
O
7
in equivalent per litre?
C
r
2
O
2
−
7
+
14
H
+
+
6
e
→
2
C
r
3
+
+
7
H
2
O
View Solution