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Standard XII
Chemistry
Charge and Current
Question
When
0.1
mol
M
n
O
2
−
4
is oxidised the quantity of electricity required to completely
M
n
O
2
−
4
to
M
n
O
4
−
is:
96500
C
2
×
96500
C
9650
C
96.50
C
A
96500
C
B
9650
C
C
96.50
C
D
2
×
96500
C
Open in App
Solution
Verified by Toppr
The oxidation reaction is as shown below.
M
n
O
2
−
4
+
e
−
→
M
n
O
−
4
Oxidation of one mole of
M
n
O
2
−
4
requires 1 mole of electrons.
Hence, the oxidation of 0.1 mole of electrons will require 0.1 mole of electrons.
This corresponds to
96500
×
0.1
=
9650
C
.
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