When $0.15kg$ of ice at $0^{o}C$ is mixed with $0.30kg$ of water at $50^{o}C$ in a container, the resulting temperature is $6.7^{o}C$. Calculate latent heat of melting of ice.
(Specific heat of water is $4.186\times 10^{3}JK{g}^{-1}$).

$20g$ of steam at $100^{\circ }C$ is passed into $100g$ of ice at $0^{\circ }C$. Find the resultant temperature if specific latent heat of steam is $540cal/g$.,specific latent heat of ice is $80cal/g$ and specific heat of water $1cal/g^{\circ }C$