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# When 0.15kg of ice at 0oC is mixed with 0.30kg of water at 50oC in a container, the resulting temperature is 6.7oC. Calculate latent heat of melting of ice. (Specific heat of water is 4.186×103JKg−1).3.69×105Jkg−1 5.46×105Jkg−1 2.23×105Jkg−1 3.34×105Jkg−1

A
5.46×105Jkg1
B
3.34×105Jkg1
C
2.23×105Jkg1
D
3.69×105Jkg1
Solution
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Q1
When 0.15kg of ice at 0oC is mixed with 0.30kg of water at 50oC in a container, the resulting temperature is 6.7oC. Calculate latent heat of melting of ice.
(Specific heat of water is 4.186×103JKg1).

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Q2
When $$0.15 \,kg$$ of ice of $$0^o C$$ mixed with $$0.30 \,kg$$ of water at $$50^o C$$ in a container, the resulting temperature is $$6.7^o C$$. calculate the heat of fusion of ice. $$(S_{water} = 4186 \,J \,kg^{-1} K^{-1})$$
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Calculate the heat required to convert 3kg of ice at 12oC kept in a calorimeter to steam at 100o at atmospheric pressure. (Given: specific heat of ice =2.100×105Jkg1K1, specific heat of water =4.186×106Jkg1, latent heat of fusion of ice =3.35×105Jkg1 and latent heat of steam =2.256×106Jkg1) .

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Q4
If 10g of ice is added to 40g of water at 15oC, then the temperature of the mixture is (specific heat of water=4.2×103Jkg1K1,Latent heat of fusion of ice =3.36×105Jkg1)
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Calculate the amount of heat required to convert 500 g of ice water without change of temperature (Lice=3.34×105Jkg1)
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