When 1.0×1022 electrons are transferred from the conductor to another, a potential difference of 10V appears between the conductors. Calculate the capacitance of the two-conductor system
1.6×10−8F
2.6×10−8F
3.6×10−8F
4.6×10−8F
A
4.6×10−8F
B
2.6×10−8F
C
1.6×10−8F
D
3.6×10−8F
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