When 50 cm-3 of a strong acid is added to 50 cm-3 of an alkali- the temperature rises by 5-oC- If 250 cm-3 of each liquid is mixed- the temperature rise would be-5-oC10-oC25-oC20-oC

Question

Toppr Admin · Accepted Answer

In a chemical reaction- reagents always react in the same gram equivalent amount- so the temp rise would be always same-Temperature rise -250cm3- each-xA0- - Temperature rise -50cm3- each-So answer is -A-

When $50 c m^{3}$ of a strong acid is added to $50 c m^{3}$ of an alkali, the temperature rises by $5^{o} C$ . If $250 c m^{3}$ of each liquid is mixed, the temperature rise would be:
$5^{o} C$
$10^{o} C$
$25^{o} C$
$20^{o} C$

In a chemical reaction, reagents always react in the same gram equivalent amount, so the temp rise would be always same.
Temperature rise $(250 c m^{3})$ each = Temperature rise $(50 c m^{3})$ each,
So answer is [A].

When 50 cm3 of a strong acid is added to 50 cm3 of an alkali, the temperature rises by 5oC. If 250 cm3 of each liquid is mixed, the temperature rise would be:5oC10oC25oC20oC

In a chemical reaction, reagents always react in the same gram equivalent amount, so the temp rise would be always same.Temperature rise (250cm3) each = Temperature rise (50cm3) each,So answer is [A].

When $50 c m^{3}$ of a strong acid is added to $50 c m^{3}$ of an alkali, the temperature rises by $5^{o} C$ . If $250 c m^{3}$ of each liquid is mixed, the temperature rise would be:
$5^{o} C$
$10^{o} C$
$25^{o} C$
$20^{o} C$

In a chemical reaction, reagents always react in the same gram equivalent amount, so the temp rise would be always same.
Temperature rise $(250 c m^{3})$ each = Temperature rise $(50 c m^{3})$ each,
So answer is [A].