When a current carrying coil is placed in a uniform magnetic field of induction B, then a torque τ acts on it. If I is the current, n is the number of turns and A is the face area of the coil and the normal to the coil makes an angle θ with B, Then
τ=BInAsinθ
τ=BInAcosθ
τ=BInA
τ=BInAtanθ
A
τ=BInAcosθ
B
τ=BInAtanθ
C
τ=BInA
D
τ=BInAsinθ
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Solution
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→τ=→M×→B →τ=MBsinθ =niABsinθ(∵M=niA)
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