When a current carrying coil is placed in a uniform magnetic field with its magnetic moment anti-parallel to the field
torque on it is maximum
dipole is in unstable equilibrium
torque on it is zero
potential energy is maximum

Question

When a current carrying coil is placed in a uniform magnetic field with its magnetic moment anti-parallel to the field
torque on it is maximum
dipole is in unstable equilibrium
torque on it is zero
potential energy is maximum

Toppr Admin · Accepted Answer

Given- -x2192-M-x2226-x2192-B- It is anti parallel-x2234-x2192-M-xD7-x2192-B-0 since angle is 180-x2218-Potential energy U-x2212-x2192-M-x2192-B-x2212-MBcos180-x2218-MB-xD7-1-MBPotential energy is maximum is an equilibrium but is an unstable equilibrium-

When a current carrying coil is placed in a uniform magnetic field with its magnetic moment anti-parallel to the fieldtorque on it is maximumdipole is in unstable equilibriumtorque on it is zeropotential energy is maximum

Given, →M∦→B, It is anti parallel.∴→M×→B=0 since angle is 180∘Potential energy U=−→M.→B=−MBcos180∘=MB×1=MBPotential energy is maximum is an equilibrium but is an unstable equilibrium.

When a current carrying coil is placed in a uniform magnetic field with its magnetic moment anti-parallel to the field
torque on it is maximum
dipole is in unstable equilibrium
torque on it is zero
potential energy is maximum

Given, $\to M ∦ \to B$ , It is anti parallel.
$∴ \to M \times \to B = 0$ since angle is $180^{\circ}$
Potential energy $U = - \to M . \to B = - M B cos 180^{\circ} = M B \times 1 = M B$
Potential energy is maximum is an equilibrium but is an unstable equilibrium.