Solve
Guides
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Standard XII
Physics
Reverse Bias
Question

When a junction diode is reverse biased, the current called drift current is due to
  1. holes of both n- and p-side.
  2. majority charge carriers of both n- and p-side.
  3. minority charge carriers of both n- and p-side.
  4. conduction band electrons of n-side only.

A
minority charge carriers of both n- and p-side.
B
majority charge carriers of both n- and p-side.
C
holes of both n- and p-side.
D
conduction band electrons of n-side only.
Open in App
Solution
Verified by Toppr

In reverse bias condition, the positive terminal is connected to the n-type and the negative terminal is connected to the p-type. Hence, majority charge carriers are swept into terminals and minority charge carriers are repelled by the terminals. Thus, a very small drift current flows through the diode due to minority charge carriers of both n-side and p-side.

Was this answer helpful?
1
Similar Questions
Q1

The dominant mechanisms for the motion of charge carriers in forward and reverse biased germanium p-n junctions are :


View Solution
Q2
The dominant mechanisms for motion of charge carriers in forward and reversed biased silicon p-n junctions are :
View Solution
Q3
Describe briefly with the help of a circuit diagram, how the flow of current carriers in a p−n−p transistor is regulated with emitter-base junction forward biased and base-collector junction reverse biased.
View Solution
Q4
The current through any p-n junction is due to
a) drift of charge carriers.
b) diffusion of charge carriers.
c) different concentrations of same type of charge carriers in different regions.
d) same concentrations of same type of charge carriers in different regions.
View Solution
Q5
When a junction diode is reverse biased, the current called drift current is due to
View Solution