Question

When the lift is stationary, his apparent weight is $W_{2}$

When the lift falls freely his apparent weight is $W_{3}$

When the lift is going down with uniform acceleration which is less than the acceleration due to gravity, his apparent weight is $W_{4}$

The increasing order of these four weights is

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Correct option is B)

When lift is stationary, $W_{2}=mg$

When lift falls freely, it accelerates with g downwards, causing an upwards pseudo force in the frame of the lift equal to mg. Hence total force is 0. So weight is 0. $W_{3}=0$

When lift accelerates down, pseudo force acts upwards, hence it decreases apparent weight $W_{4}<mg$, but also the acceleration is less than g, therefore $W_{4}=m(g−a)>0$

Hence, $W_{3}<W_{4}<W_{2}<W_{1}$

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