0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

When a monochromatic light of frequency v is incident on a metal, stopping potential is V0. Frequency of the incident light for which stopping potential becomes double is :
  1. v
  2. v+eV0h
  3. 2veV0h
  4. veV0h

A
v
B
2veV0h
C
v+eV0h
D
veV0h
Solution
Verified by Toppr

hv=hv0+K.E

At stopping potential, K.E=eV

hv=hv0+eV

V=he(vv0)

Given for, V=V0;v=v.

V0=he(vv0)

For V=2V0;v1=?

2V0=(he(v1v0))

v1=2eV0h+v0

Was this answer helpful?
1
Similar Questions
Q1
When a monochromatic light of frequency v is incident on a metal, stopping potential is V0. Frequency of the incident light for which stopping potential becomes double is :
View Solution
Q2
The stopping potential for photoelectrons from a metal surface is V1 when monochromatic light of frequency ν1 is incident on it. The stopping potential becomes V2 when monochromaitc light of another frequency is incident on the same metal surface. If h be the Planck's constant and e be the charge of an electron then the frequency of light in the second case is
View Solution
Q3
The stopping potential for photoelectrons from a metal surface is V1 when monochromatic light of frequency v1 is incident on it. The stopping potential becomes V2 when monochromatic light of another frequency is incident on the same metal surface. If h be the Plancks onstant and e be the charge of an electron, then the frequency of light in the second case is
View Solution
Q4
When a certain photosensitive surface is illuminated with monochromatic light of frequency v, the stopping potential for the photocurrent is V02. When the surface is illuminated by monochromatic light of frequency v2, the stopping potential is V0. the threshold frequency for photoelectric emission is:
View Solution
Q5
When light of frequency 2.2×1015Hz is incident on a metal surface, photoelectrons emitted can be stopped by a retarding potential of 6.6 V. For light of frequency 4.6×1015Hz, the reverse potential is 16.5 V. Find h
View Solution