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# When a proton is released from rest in room, it starts with an initial acceleration a0 towards west When it is projected towards north with a speed V0 it moves with an initial acceleration 3a0 towards west. The electric and magnetic fields in the room are :ma0eeast,3ma0ev0downma0ewest,3ma0ev0upma0eeast,3ma0ev0upma0ewest,2ma0ev0down

A
ma0eeast,3ma0ev0down
B
ma0eeast,3ma0ev0up
C
ma0ewest,3ma0ev0up
D
ma0ewest,2ma0ev0down
Solution
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#### Initial acceleration =a0when a proton is released from rest in a room it starts with an initial acceleration a0 towards west.F1= electric force acting on the proton in west directionq= charge on protonE= electric field in the region in west directionm= mass of protonelectric force on the proton can be given on F1=qEUsing Newton's second lawF1=ma0hence,ma0=qEE=ma0/q Along westCase -2V0= initial velocity of the particleF2= magnetic force acting on the proton in west direction electric force on proton =3ma0F1+F2=3ma0ma0+F2=3ma0maximum magnetic force is given by F2=qV0BSo, qV0B=2ma0B=2ma0/qV0 (down).Option C

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