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# When a proton is released from the rest in a room, it starts with an initial acceleration a0 towards north with a speed v0 it moves with an initial acceleration 3a0 towards west. The electric and magnetic fields in the room arema0e west, 2ma0ev0 upma0e west, 2ma0ev0 downma0e east, 3ma0ev0 downma0e west, 3ma0ev0 up

A
ma0e west, 2ma0ev0 down
B
ma0e west, 2ma0ev0 up
C
ma0e east, 3ma0ev0 down
D
ma0e west, 3ma0ev0 up
Solution
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#### a0=eEm⇒E=ma0e

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