When a simple pendulum is taken from the Equator to the Pole, its period of oscillation will :

Question

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Answer 1

Time period of simple pendulum is given by $T = 2 π \frac{l}{g}$
where $l$ is the length of the pendulum and $g$ is the acceleration due to gravity.
We know that $g_{p o l e} > g_{e q u a t o r}$
$⟹ T_{p o l e} < T_{e q u a t o r}$
Thus time period of simple pendulum decreases when it is taken from equator to pole.

Answer 2

Time period of simple pendulum is given by

T = 2 π \frac{l}{g}

where

l

is the length of the pendulum and

g

is the acceleration due to gravity.

We know that

g_{p o l e} > g_{e q u a t o r}

⟹ T_{p o l e} < T_{e q u a t o r}

Thus time period of simple pendulum decreases when it is taken from equator to pole.