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When a source moves away from a stationary observer, the frequency is $$ 6/7 $$ times the original frequency. Given: speed of sound = $$ 330\,m/s $$ . The speed of the source is

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Solution

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$$ \nu' = \dfrac{\nu}{\nu + \nu,}\nu $$

or $$ \dfrac{6}{7} \nu = \dfrac{330}{330 + \nu,}\nu $$

or $$ 6 \times 330 + 6 \nu, = 7 \times 330 $$

or $$ 6 \nu, = 330 $$ or $$ \nu, = 55\,m/s $$

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