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Question

When air is replaced by a dielectric medium of force constant K, the maximum force of attraction between two charges, separated by a distance :
decreases K times
increases K times
remains unchanged
becomes $\frac{1}{K^{2}}$ times

A

decreases K times

B

remains unchanged

C

increases K times

D

becomes

\frac{1}{K^{2}}

times

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Solution

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In air the force of attraction between two charges is $F_{a} = \frac{1}{4 π ϵ_{0}} \frac{q_{1} q_{2}}{r^{2}}$
In dielectric medium the force of attraction between two charges is $F_{d} = \frac{1}{4 π K ϵ_{0}} \frac{q_{1} q_{2}}{r^{2}} = \frac{F_{a}}{K}$
Thus, force decreases K-times.

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