When conc. $H_{2} {S O}_{4}$ is heated with $P_{2} O_{5}$ , the acid is converted into:
sulphur trioxide
sulphur dioxide
sulphur
a mixture of sulphur dioxide and sulphur trioxide

sulphur dioxide

a mixture of sulphur dioxide and sulphur trioxide

sulphur trioxide

sulphur

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Solution

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Sulphur trioxide is prepared by heating concentrated sulphuric acid with a large excess of phosphorus pentoxide, $P_{2} O_{5}$ .

$H_{2} S O_{4} + P_{2} O_{5} \to S O_{3} + 2 H P O_{3}$
Hence, option $A$ is correct.

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When conc.

H_{2} {S O}_{4}

is heated with

P_{2} O_{5}

, the acid is converted into:

View Solution

In the Contact process, sulphur trioxide is not converted to sulphuric acid by reacting it with water. Instead a two-step procedure is used. The equations for the two steps involved are:

{S O}_{x} + H_{2} {S O}_{4} \to H_{2} S_{2} O_{y} H_{2} S_{2} O_{7} + H_{2} O \to 2 H_{2} {S O}_{4}

Find the value of x and y :

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(a) Name the catalyst which helps in the conversion of sulphur dioxide to sulphur trioxide in step C.
(b) In the Contact process for the manufacture of the sulphuric acid, sulphur trioxide is not converted to sulphuric acid by reacting it with water. Instead, a two-steps procedure is used. Write the equations for the two steps involved in D.
(c) What type of substance will liberate sulphur dioxide from sodium sulphite to step E?
(d) Write the equation for the reaction by which sulphur dioxide is converted to sodium sulphite in step F.
[5 MARKS]

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(i) Name the catalyst which helps in the conversion of sulphur dioxide to sulphur trioxide in step C.
(ii) In the contact process for the manufacture of sulphuric acid, sulphur trioxide is not converted to sulphuric acid by reacting it with water. Instead a two-step procedure is used. Write the equations for the two step involved in D.
(iii) What type of substance will liberate sulphur dioxide from sodium sulphite in step E?
(iv) Write the equation for the reaction by which sulphur dioxide is converted to sodium sulphite in step F?

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Give reasons for the following:
(i) In the contact process, sulphur trioxide formed is dissolved in 98% sulphuric acid and not in water.
(ii) When solution of sulphur dioxide is exposed to air, it gets converted to sulphuric acid.
(iii) When diluting concentrated sulphuric acid, the acid should be added to water and not water to the acid.
(iv) When concentrated sulphuric acid is exposed to air, its volume increases and it becomes slightly dilute.
(v) Sulphuric acid can form two kinds of salts with sodium chloride.
(vi) When barium chloride is added to dilute sulphuric acid, a white precipitate is formed.
(vii) When carbon is heated with concentrated sulphuric acid, carbon dioxide is formed.
(viii) Ammonia gas cannot be dried by passing through concentrated sulphuric acid.
(ix) When concentrated sulphuric acid is added to sugar/glucose, a black mass is left behind.
(x) Concentrated sulphuric acid should not be added to oxalic acid or formic acid in the open laboratory.
(xi) When concentrated sulphuric acid is added to blue crystalline copper sulphate, it turns powdery white.
(xii) Concentrated sulphuric acid must be stored in airtight bottles.
(xiii) Cotton clothes get burnt with concentrated sulphuric acid.
(xiv) H₂SO₄ cannot be prepared by heating sodium sulphate with conc. HCl or HNO₃.

View Solution

When conc. H2SO4 is heated with P2O5, the acid is converted into:sulphur trioxidesulphur dioxidesulphura mixture of sulphur dioxide and sulphur trioxide

Sulphur trioxide is prepared by heating concentrated sulphuric acid with a large excess of phosphorus pentoxide, P2O5.H2SO4+P2O5→SO3+2HPO3Hence, option A is correct.

When conc. $H_{2} {S O}_{4}$ is heated with $P_{2} O_{5}$ , the acid is converted into:
sulphur trioxide
sulphur dioxide
sulphur
a mixture of sulphur dioxide and sulphur trioxide

Sulphur trioxide is prepared by heating concentrated sulphuric acid with a large excess of phosphorus pentoxide, $P_{2} O_{5}$ .

$H_{2} S O_{4} + P_{2} O_{5} \to S O_{3} + 2 H P O_{3}$
Hence, option $A$ is correct.