When dil- - H - 2 -S- O - 4 - is added to aqueous solution of potassium chromate- yellow colour of solution turns to orange colour- It indicates -chromate ions are reducedoxygen gets removed from chromate ionsmono-centric complex is converted into dicentric complexchromate ions are oxidized

Question

Toppr Admin · Accepted Answer

The correct option is B chromate ions are oxidized
When dil. $H_{2} S O_{4}$ is added to the yellow solution of $K_{2} C r O_{4}$ yellow colour changes to orange red due to the formation of $K_{2} {C r}_{2} O_{7}$ .
$2 K_{2} C r O_{4} + H_{2} S O_{4} ⟶ K_{2} {C r}_{2} O_{7} + K_{2} S O_{4} + H_{2} O$
Above reaction shows that the monocentric complex $(K_{2} C r O_{4})$ is converted into dicentric $(K_{2} {C r}_{2} O_{7})$ complex and it can be explained with the help of diagram.

When dil. H2SO4 is added to aqueous solution of potassium chromate, yellow colour of solution turns to orange colour. It indicates :chromate ions are reducedoxygen gets removed from chromate ionsmono-centric complex is converted into dicentric complexchromate ions are oxidized

When dil. $H_{2} S O_{4}$ is added to aqueous solution of potassium chromate, yellow colour of solution turns to orange colour. It indicates :
chromate ions are reduced
oxygen gets removed from chromate ions
mono-centric complex is converted into dicentric complex
chromate ions are oxidized