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Question

When heavy water reacts with calcium carbide, the product formed is:
acetylene
calcium hydroxide
deuterium
deutero acetylene

A

deutero acetylene

B

acetylene

C

calcium hydroxide

D

deuterium

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Solution

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When heavy water reacts with calcium carbide, the products formed are deutero acetylene $(C_{2} D_{2})$ and calcium deuteroxide $(C a (O D)_{2})$ .
The reaction is as follows:
$C a C_{2} + 2 D_{2} O \to C_{2} D_{2} + C a (O D)_{2}$
Hence, option D is the correct answer.

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