When molten salt was electrolysed 5 min with 9-65 A current - 0-18 g of the metal was deposited-Calculate the Eq- mass of metal-

Question

Toppr Admin · Accepted Answer

Correct option is A- -6-10-begin-aligned-10-text - Equivalent wt- - -amp-frac-w -times 96500-1 -times t- -10-amp-frac-0-18 -times 96500-9-65 -times 5 -times 60-6 -10-text - So the eq - -amp- -text - mass of metal is - 6 -10-end-aligned-10-

when molten salt was electrolysed for $$5$$ min with $$9.65\ A$$ current , $$0.18\ g$$ of the metal was deposited.
Calculate the Eq. mass of metal.

Correct option is A. $$6$$
$$ \begin{aligned} \text { Equivalent wt. } &=\frac{w \times 96500}{1 \times t} \\ &=\frac{0.18 \times 96500}{9.65 \times 5 \times 60}=6 \\ \text { So the eq } & \text { mass of metal is } 6 . \end{aligned} $$

when molten salt was electrolysed for $$5$$ min with $$9.65\ A$$ current , $$0.18\ g$$ of the metal was deposited.Calculate the Eq. mass of metal.

Correct option is A. $$6$$$$ \begin{aligned} \text { Equivalent wt. } &=\frac{w \times 96500}{1 \times t} \\ &=\frac{0.18 \times 96500}{9.65 \times 5 \times 60}=6 \\ \text { So the eq } & \text { mass of metal is } 6 . \end{aligned} $$

when molten salt was electrolysed for $$5$$ min with $$9.65\ A$$ current , $$0.18\ g$$ of the metal was deposited.
Calculate the Eq. mass of metal.

Correct option is A. $$6$$
$$ \begin{aligned} \text { Equivalent wt. } &=\frac{w \times 96500}{1 \times t} \\ &=\frac{0.18 \times 96500}{9.65 \times 5 \times 60}=6 \\ \text { So the eq } & \text { mass of metal is } 6 . \end{aligned} $$