Question

When photons of energy $h\nu$ are incident on the surface of photosensitive material of work function $h{\nu }_0,$ then

• A. The kinetic energy of all emitted electrons is $h{v}_0$
• B. The kinetic energy of all emitted electrons is $h(v-v_0)$
• C. The kinetic energy of all fastest electrons is $h(v-v_0)$
• D. The kinetic energy of all emitted electrons is $hv$

Answer 1

Answer: (C)

The maximum kinetic energy ($K_{max}$) of the photoelectrons to the frequency of the absorbed photons ($\nu$) and the threshold frequency (${\nu }_o$) of the photoemissive surface.
$K_{max}=h(\nu -{\nu }_o)$

So, the answer is option (C).