When the distance between two charged particles is halved, then the force between them becomes :
Double
One-fourth
Half
Four times
A
One-fourth
B
Half
C
Double
D
Four times
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Solution
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Earlier force between
two particles is
F=kq1q2r2
When distance is halved
force becomes
F′=kq1q2(r/2)2=4kq1q2r2=4F
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