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Question

When the light of frequency 2v0 (where v0 is threshold frequency), is incident on a metal plate, the maximum velocity of electrons emitted is v1. When the frequency of the incident radiation is increased to 5v0, the maximum velocity of electrons emitted from the same plate is v2. The ratio of v1 to v2 is?4:11:21:42:1

A
1:4
B
2:1
C
4:1
D
1:2
Solution
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We know that, K.E.=hν−ϕ0where ϕ can be written as hν0When ν=2ν0K.E.1=mv212=2hν0−hν0V1=√2hν0mSimilarly we can find that V2=√4hν0mHence,V1V2=1/2

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