When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volumes of hydrogen evolved is:

Question

When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide- the ratio of volumes of hydrogen evolved is-1 - 21 - 12 - 19 - 4

Toppr Admin · Accepted Answer

The reactions of zinc with sulphuric acid and excess of sodium hydroxide separately are given below:
$Z n + 2 N a O H \to N a_{2} Z n O_{2} + H_{2}$
$Z n + H_{2} S O_{4} \to Z n S O_{4} + H_{2}$
In both the reactions, $1$ mole of $H_{2}$ is evolved.
Hence, the ratio of volumes of hydrogen evolved is $1 : 1$ .

When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volumes of hydrogen evolved is__________.1:21:12:19:4

The reactions of zinc with sulphuric acid and excess of sodium hydroxide separately are given below:Zn+2NaOH→Na2ZnO2+H2Zn+H2SO4→ZnSO4+H2In both the reactions, 1 mole of H2 is evolved.Hence, the ratio of volumes of hydrogen evolved is 1:1.

When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volumes of hydrogen evolved is__________.
$1 : 2$
$1 : 1$
$2 : 1$
$9 : 4$