When two condensers of capacitance 1μF and 2μF are connected is series then the effective capacitance will be :
23μF
3μF
32μF
4μF
A
23μF
B
32μF
C
3μF
D
4μF
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Solution
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When two condenser are in series , the equivalent capacitance Ceq=C1C2C1+C2=1×21+2=23μF
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