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Question

Where will the hand of a clock stop if it -
In $$1$$ complete clock wise revolution the hand of a clock will rotate by $$360^{\circ}$$.
Starts at $$12$$ and makes $$\dfrac {1}{2}$$ of a revolution, clockwise?

Solution
Verified by Toppr

If the hand of the clock start $$12$$ and makes $$\dfrac {1}{2}$$ of a revolution, clockwise, it will rotate by $$180^{\circ}$$ and hence, it will stop at $$6$$.

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