Solve
Guides
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Standard XII
Chemistry
Question

Which of the following alkanes can be synthesized by the Wurtz reaction in good yield?
  1. CH3−CH2−C(CH3)2CH2−CH3
  2. (CH3)2CH−CH2−CH(CH3)2
  3. (CH3)3C−CH2−CH2−CH3
  4. (CH3)2CH−CH2−CH2−CH(CH3)2

A
(CH3)2CH−CH2−CH2−CH(CH3)2
B
CH3−CH2−C(CH3)2CH2−CH3
C
(CH3)2CH−CH2−CH(CH3)2
D
(CH3)3C−CH2−CH2−CH3
Open in App
Solution
Verified by Toppr

Symmetrical alkane with even number of carbon atoms can be prepared by Wurtz reaction.

Wurtz reaction is the reaction of symmetrical alkyl halide in the presence of Na in dry ethyl ether to give the symmetrical higher alkane as the product.
So, according to the given option the best yield can be obtained is for the symmetrical yield alkane.

Hence , Option B is correct .

Was this answer helpful?
2
Similar Questions
Q1
Homolytic fission of the following alkanes forms free radicals
CH3−CH3,CH3−CH2−CH3,(CH3)2CH−CH3,CH3−CH2−CH(CH3)2.
The increasing order of stability of the radicals is:

View Solution
Q2
Rank the following cations in decreasing order of stability.
(CH3)2CH−CH2−C+H2
CH3−C+H−CH(CH3)2
CH3−C+(CH3)−CH2−CH3
View Solution
Q3
Number of carbanions which are more stable than ⊖CH2−CH3

(i) ⊖CH3 (ii) ⊖CF3 (iii) ⊖CH(CH3)2 (iv) ⊖CCl3 (v) ⊖CH2−CCl3 (vi) ⊖CH2−CH2−CH3

(vii) ⊖CH2−⊕N(CH3)3 (viii) ⊖C(CH3)3 (ix) ⊖CH2−CD3 :

View Solution
Q4
Homolytic fission of the following alkanes forms free radicals
CH3−CH3,CH3−CH2−CH3,(CH3)2CH−CH3,CH3−CH2−CH(CH3)2.
The increasing order of stability of the radicals is:

View Solution
Q5
The correct IUPAC name of the compound is:

CH3−CH2−CH2−CH3|CH−CH−C(C2H5)3|CH(CH3)2

View Solution