Which of the following compound can show tautomerism ?
Correct option is B.
Correct Answer: Option B
Explanation of correct option:
For tautomerism, there should be at least one $$\alpha-H$$ on the $$sp^3$$ hybridized carbon atom. In option B, there are $$\alpha-H$$, so tautomerism is possible in option B.
Explanation of incorrect options:
In the other options, there is no $$\alpha-H$$ present. So tautomerism is not possible.